Question:

Which one amongst the following are good oxidizing agents?
(A) \( \text{Sm}^{\text{2+}}\)
(B) \(\text{Ce}^{\text{2+}}\)
(C)\( \text{Ce}^{\text{4+}}\)
(D) \(\text{Tb}^{\text{4+}}\)
Choose the most appropriate answer from the options given below:

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Good oxidizing agents are species that readily accept electrons to attain a stable oxidation state.

Updated On: Jan 8, 2025
  • C only

  • C and D only

  • A and B only

  • D only

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The Correct Option is B

Solution and Explanation

• Ce4+ acts as a good oxidizing agent because it readily accepts electrons to attain the more stable Ce3+ configuration.
• Tb4+ also acts as a good oxidizing agent because it gets reduced to the more stable Tb3+ configuration.
• Sm2+ and Ce2+ are reducing agents as they tend to lose electrons to attain stable configurations.
Thus, the good oxidizing agents are Ce4+ and Tb4+.

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Concepts Used:

D and F Block Elements

The d-block elements are placed in groups 3-12 and F-block elements with 4f and 5f orbital filled progressively. The general electronic configuration of d block elements and f- block elements are (n-1) d 1-10 ns 1-2 and (n-2) f 1-14 (n-1) d1 ns2 respectively. They are commonly known as transition elements because they exhibit multiple oxidation states because of the d-d transition which is possible by the availability of vacant d orbitals in these elements. 

They have variable Oxidation States as well as are good catalysts because they provide a large surface area for the absorption of reaction. They show variable oxidation states to form intermediate with reactants easily. They are mostly lanthanoids and show lanthanoid contraction. Since differentiating electrons enter in an anti-penultimate f subshell. Therefore, these elements are also called inner transition elements.

Read More: The d and f block elements