The balanced chemical reaction is:
\[ 2 \text{KI} + 2 \text{K}_3[\text{Fe(CN)}_6] \xrightarrow{\text{H}^+} \text{I}_2 + 2 \text{K}_4[\text{Fe(CN)}_6] \]
From the reaction, 2 moles of KI react with 2 moles of \( \text{K}_3[\text{Fe(CN)}_6] \) to produce 1 mole of \( \text{I}_2 \) and 2 moles of \( \text{K}_4[\text{Fe(CN)}_6] \).
The stoichiometric ratio between KI and \( \text{K}_3[\text{Fe(CN)}_6] \) is 1:1.
If 2 moles of \( \text{K}_3[\text{Fe(CN)}_6] \) are used, 2 moles of KI are required.
\[ \text{K}_4[\text{Fe(CN)}_6] + 3\text{ZnCl}_2 \rightarrow \text{K}_2\text{Zn}_3[\text{Fe(CN)}_6]_2 + 6\text{KCl} \]
In this reaction, 3 zinc ions are incorporated into the product \( \text{K}_2\text{Zn}_3[\text{Fe(CN)}_6]_2 \).
\[ \text{K}_4[\text{Fe(CN)}_6] + 2\text{ZnCl}_2 \rightarrow \text{Zn}_2[\text{Fe(CN)}_6] + 4\text{KCl} \]
In this reaction, 2 zinc ions are incorporated into the product \( \text{Zn}_2[\text{Fe(CN)}_6] \).
The reaction pathway determines whether 2 or 3 zinc ions participate in the formation of the final product.