According to the law of reflection:
\[ i = r, \]
where \( i \) is the angle of incidence. Therefore:
\[ i = 30^\circ. \]
The angle of deviation (\( \delta \)) is the angle between the incident ray and the reflected ray. It is given by:
\[ \delta = 180^\circ - 2i. \]
Since \( i = 30^\circ \), substitute the value into the formula:
\[ \delta = 180^\circ - 2(30^\circ). \]
Simplify the expression:
\[ \delta = 180^\circ - 60^\circ = 120^\circ. \]
The angle of deviation is \( 120^\circ \).
A current element X is connected across an AC source of emf \(V = V_0\ sin\ 2πνt\). It is found that the voltage leads the current in phase by \(\frac{π}{ 2}\) radian. If element X was replaced by element Y, the voltage lags behind the current in phase by \(\frac{π}{ 2}\) radian.
(I) Identify elements X and Y by drawing phasor diagrams.
(II) Obtain the condition of resonance when both elements X and Y are connected in series to the source and obtain expression for resonant frequency. What is the impedance value in this case?
Let $ P_n = \alpha^n + \beta^n $, $ n \in \mathbb{N} $. If $ P_{10} = 123,\ P_9 = 76,\ P_8 = 47 $ and $ P_1 = 1 $, then the quadratic equation having roots $ \alpha $ and $ \frac{1}{\beta} $ is: