Question:

When metal ? $M$ ? is treated with $NaOH$, a white gelatinous precipitate ?$X$? is obtained, which is soluble in excess of $NaOH$. Compound ?$X$? when heated strongly gives an oxide which is used in chromatography as an adsorbent. The metal ?$M$? is :

Updated On: Jun 24, 2024
  • Zn
  • Ca
  • Al
  • Fe
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The Correct Option is C

Solution and Explanation

$Al ^{3+} {->[{ NaOH }]} \underset{\text{White gelatinous ppt.}}{ Al ( OH )_{3} \downarrow} {->[{{\text{ Excess}}}\,{ NaOH }]} \underset{\text{Sodium meta aluminate (soluble)}}{NaAlO _{2}}$
$2 Al ( OH )_{3} {->[{\text { Strong heating }}]} Al _{2} O _{3}+3 H _{2} O$
$Al _{2} O _{3}$ is used in column chromatography.
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Concepts Used:

P-Block Elements

  • P block elements are those in which the last electron enters any of the three p-orbitals of their respective shells. Since a p-subshell has three degenerate p-orbitals each of which can accommodate two electrons, therefore in all there are six groups of p-block elements.
  • P block elements are shiny and usually a good conductor of electricity and heat as they have a tendency to lose an electron. You will find some amazing properties of elements in a P-block element like gallium. It’s a metal that can melt in the palm of your hand. Silicon is also one of the most important metalloids of the p-block group as it is an important component of glass.

P block elements consist of: