Question:
When equal volume of 1M HCl and 1M H$_2$SO$_4$ are separately neutralized by excess volume of 1M NaOH solution, X and Y kJ of heat is liberated respectively. The value of Y/X is ____.
When equal volume of 1M HCl and 1M H$_2$SO$_4$ are separately neutralized by excess volume of 1M NaOH solution, X and Y kJ of heat is liberated respectively. The value of Y/X is ____.
Updated On: Nov 23, 2024
Hide Solution
Verified By Collegedunia
Correct Answer: 2
Solution and Explanation
Neutralization reactions:
\( \mathrm{H^+ + OH^- \rightarrow H_2O} \quad (\text{from HCl: } X), \)
\( \mathrm{2H^+ + 2OH^- \rightarrow 2H_2O} \quad (\text{from } H_2SO_4: Y). \)
From the reactions:
\( Y = 2X \implies \frac{Y}{X} = 2. \)
Final Answer: 2.
Was this answer helpful?
0
0
Top Questions on Enthalpy change
- The bond dissociation energies of gaseous H2, Cl2, and HCl are 104, 58, and 103 kcal, respectively. The enthalpy of formation of HCl gas would be:
- BCECE - 2025
- Chemistry
- Enthalpy change
- What is the enthalpy of neutralization for CH3COOH + NaOH?
- BCECE - 2025
- Chemistry
- Enthalpy change
- The electron gain enthalpy (Cl2,H) of chlorine is -3.7 eV mol-1. How much energy (in kcal mol-1) is released when 71 g of chlorine atoms are completely converted into Cl- ions in gaseous state? (1 eV = 23 kcal)
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
- Calculate the enthalpy change ($\Delta H$) for the combustion of 1 mole of methane ($\mathrm{CH}_4$) given the reaction: $$ \mathrm{CH}_4(g) + 2 \mathrm{O}_2(g) \rightarrow \mathrm{CO}_2(g) + 2 \mathrm{H}_2 \mathrm{O}(l) $$ Given bond energies: C–H = 413 kJ/mol, O=O = 498 kJ/mol, C=O = 803 kJ/mol, O–H = 467 kJ/mol.
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
The enthalpy of combustion of methane is 890 kJ/mol. How much heat is released when 8 g of methane is burned completely? (Molar mass of CH\(_4\) = 16 g/mol)
- AP EAPCET - 2025
- Chemistry
- Enthalpy change
View More Questions
Questions Asked in JEE Main exam
- Let \( f(x) = \frac{x - 5}{x^2 - 3x + 2} \). If the range of \( f(x) \) is \( (-\infty, \alpha) \cup (\beta, \infty) \), then \( \alpha^2 + \beta^2 \) equals to.
- JEE Main - 2025
- Functions
- CrCl\(_3\).xNH\(_3\) can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558°C. Assuming 100\% ionization of this complex and coordination number of Cr is 6, the complex will be:
- JEE Main - 2025
- Colligative Properties
- Suppose that the number of terms in an A.P. is \( 2k, k \in \mathbb{N} \). If the sum of all odd terms of the A.P. is 40, the sum of all even terms is 55, and the last term of the A.P. exceeds the first term by 27, then \( k \) is equal to:
- JEE Main - 2025
- Arithmetic Progression
- If \( \alpha + i\beta \) and \( \gamma + i\delta \) are the roots of the equation \( x^2 - (3-2i)x - (2i-2) = 0 \), \( i = \sqrt{-1} \), then \( \alpha\gamma + \beta\delta \) is equal to:
- JEE Main - 2025
- Complex numbers
- Let \( [x] \) denote the greatest integer function, and let \( m \) and \( n \) respectively be the numbers of the points, where the function \( f(x) = [x] + |x - 2| \), \( -2<x<3 \), is not continuous and not differentiable. Then \( m + n \) is equal to:
- JEE Main - 2025
- Differential Equations
View More Questions