To solve the problem, we need to determine the original length of a metal wire based on its change in length when subjected to different tensions.
1. Understanding the Problem:
When a tension \( F_1 \) is applied to the wire, its length is \( L_1 \). When the tension is increased to \( F_2 \), the length becomes \( L_2 \). We are tasked with finding the original length of the wire, which is the length when no force is applied (denoted as \( L_0 \)).
2. Concept of Hooke's Law:
According to Hooke's Law, the elongation or compression of a wire is directly proportional to the applied force. The change in length, \( \Delta L \), is related to the applied force \( F \) and the original length \( L_0 \) by the equation: \[ \Delta L = \frac{F}{k} \] where \( k \) is the spring constant. In this case, the difference in length is due to the change in tension, so we have the following two relations:
\( L_1 = L_0 + \Delta L_1 = L_0 + \frac{F_1}{k} \)
\( L_2 = L_0 + \Delta L_2 = L_0 + \frac{F_2}{k} \)
Now, solving for \( L_0 \) (the original length), we can rearrange the equations and find that the original length is: \[ L_0 = \frac{F_2 L_1 - F_1 L_2}{F_2 - F_1} \]
3. Conclusion:
Based on the above calculation, the correct formula for the original length of the wire is:
Final Answer:
The correct option is (B) \( \frac{F_2 L_1 - F_1 L_2}{F_2 - F_1} \).
A body of mass 1000 kg is moving horizontally with a velocity of 6 m/s. If 200 kg extra mass is added, the final velocity (in m/s) is: