What will be the effect on the root mean square velocity of oxygen molecules if the temperature is doubled and oxygen molecule dissociates into atomic oxygen?
The correct answer is (B) : The velocity of atomic oxygen doubles As \(v_{rms}=\sqrt{\frac{3RT}{M_0}}\) T is doubled and oxygen molecule is dissociated into atomic oxygen molar mass is halved. So, \(v'_{rms}=\sqrt{\frac{3R×2T_0}{M_0/2}}=2v_{rms}\) So velocity of atomic oxygen is doubled.
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