What is ‘Y’ in the following set of reactions?
Ozonolysis of alkenes results in the cleavage of the double bond, producing aldehydes or ketones. When dealing with hydration reactions, always apply Markovnikov's rule to determine the major product.
Step 1: Understanding the Reaction Sequence
1. Step 1: Acid-Catalyzed Hydration of Alkene
- The given compound \( C_4H_8 \) is an alkene.
- In the presence of sulfuric acid (\( H_2SO_4 \)) and water, Markovnikov's rule applies, leading to the formation of a more substituted alcohol.
2. Step 2: Ozonolysis Reaction
- The alcohol undergoes ozonolysis (\( O_3 \), Zn/H_2O), which cleaves the double bond and forms aldehydes or ketones depending on the structure of the starting alkene.
Step 2: Identifying 'Y'
\flushleft - The given reactant is butene (\( C_4H_8 \)).
- Hydration leads to the formation of butan-2-ol as the intermediate product.
- Ozonolysis of butan-2-ol results in acetone (\( CH_3COCH_3 \)) and formaldehyde (\( HCHO \)).
Step 3: Evaluating the Given Options
- Option (1): Incorrect, as it does not match the expected ozonolysis products.
- Option (2): Correct, as it represents acetone and formaldehyde.
- Option (3): Incorrect, as it does not correspond to the reaction mechanism.
- Option (4): Incorrect, as it represents a different structural outcome.
Thus, the correct answer is
Option (2).
The alkane which is next to methane in the homologous series can be prepared from which of the following reactions?
An alkene X on ozonolysis gives a mixture of Propan-2-one and methanal. What is X?
List-I | List-II | ||
(A) | Cyanocobalamine | (I) | Hydrogenation of Alkenes |
(B) | Wilkinson catalyst | (II) | Antipernicious anemia factor |
(C) | D-penicillamine | (III) | Refining of Ni |
(D) | Mond's Process | (IV) | Treatment of toxic effects of copper |
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