Question

Arrange the following in the increasing order of oxidation number of nitrogen
A. N$_2$O
B. NO$_3^-$
C. NO
D. NO$_2$

• A. B, D, C, A
• B. A, C, D, B
• C. A, C, B, D
• D. A, B, C, D

Hint:

Calculate oxidation number: sum to zero for neutral molecules, to ion charge for ions. Oxygen typically -2. List and compare oxidation states. Verify molecular charges.

Answer 1

The Correct Option is B

1. Oxidation number of N: Assign based on rules (O = -2, charge for ions).
2. A. N$_2$O: 2N + (-2) = 0, N = +1.
3. B. NO$_3^-$: N + 3(-2) = -1, N = +5.
4. C. NO: N + (-2) = 0, N = +2.
5. D. NO$_2$: N + 2(-2) = 0, N = +4.
6. Order: +1 (N$_2$O)<+2 (NO)<+4 (NO$_2$)<+5 (NO$_3^-$), so A, C, D, B. Thus, (2).