In polyatomic structures, count sigma and pi bonds systematically by identifying single and double bonds.
The structure of pyrophosphoric acid (H4P2O7) consists of an O=P-O-P=O backbone with terminal hydroxyl groups (OH).
Total sigma bonds: 12 (8 single P-O and O-H bonds + 4 sigma components from P=O bonds).
Total pi bonds: 2 (from P=O bonds).
\[ \frac{\sigma}{\pi} = \frac{12}{2} = 6 \]
The ratio of sigma to pi bonds in pyrophosphoric acid is 6:1.
Given below are two statements.
In the light of the above statements, choose the correct answer from the options given below:
Given below are two statements:
Statement I: Nitrogen forms oxides with +1 to +5 oxidation states due to the formation of $\mathrm{p} \pi-\mathrm{p} \pi$ bond with oxygen.
Statement II: Nitrogen does not form halides with +5 oxidation state due to the absence of d-orbital in it.
In the light of the above statements, choose the correct answer from the options given below:
Given below are the pairs of group 13 elements showing their relation in terms of atomic radius. $(\mathrm{B}<\mathrm{Al}),(\mathrm{Al}<\mathrm{Ga}),(\mathrm{Ga}<\mathrm{In})$ and $(\mathrm{In}<\mathrm{Tl})$ Identify the elements present in the incorrect pair and in that pair find out the element (X) that has higher ionic radius $\left(\mathrm{M}^{3+}\right)$ than the other one. The atomic number of the element (X) is
Match List-I with List-II.
Choose the correct answer from the options given below :