To determine the major product formed by the reaction of HI with the given compound, we need to understand the mechanism of reaction with HI (hydrogen iodide).
Hydrogen iodide (HI) is a strong acid that can cleave ether linkages through a nucleophilic substitution reaction. The reaction proceeds with the attack of the iodide ion (I-) on the carbon atom adjacent to the oxygen, followed by the breakdown of the C-O bond.
Let us analyze the possible product formation:
The reaction of HI with ethers usually results in the cleavage of the ether to give an alcohol and an alkyl iodide.
The mechanism involves protonation of the ether oxygen by the HI, followed by nucleophilic attack of the iodide ion on the more substituted carbon, due to its ability to stabilize a positive charge better.
Now, let's examine the provided images and options. One of the given structures is an ether, and our goal is to identify which option forms the major product after the HI reaction:
An ether chain will break to form an alcohol and an alkyl iodide. Considering the most stable carbocation intermediate and the provided images, the reaction involves cleavage favoring the most substituted carbon, leading us to the correct product.
The major product from this reaction is the one depicted in the following option:
This product forms because the iodide ion attacks the more accessible and stable carbon, leading to the corresponding alkyl iodide after the ether is cleaved.
An alkene or cycloalkene is indicated by the suffix (ending) ene.
For the root name, the longest chain must include both carbon atoms of the double bond.
The root chain must be numbered beginning at the end closest to a double bond carbon atom. If the double bond is in the chain's centre, the nearest substituent rule is used to determine where the numbering begins.
If the compound contains more than one double bond, it is named with a diene, triene, or equivalent prefix indicating the number of double bonds, and each double bond is assigned a locator number.
