Electric lines are perpendicular to equipotential surface
Work done is zero
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The Correct Option isB
Solution and Explanation
An equipotential surface is a surface with a constant value of potential at all points on the surface. For a uniform electric field, say, along the $x$-axis, the equipotential surfaces are planes normal to the $x$-axis, ie, plane parallel to the $y-z$ plane. Equipotential surfaces for a dipole and its electric field lines are shown in figure.
As said above that on equipotential surface, potential at all points is constant, this means that on equipotential surface work done in moving a test charge from one point to other point is zero.
In the year 1911, Rutherford discovered the atomic nucleus along with his associates. It is already known that every atom is manufactured of positive charge and mass in the form of a nucleus that is concentrated at the center of the atom. More than 99.9% of the mass of an atom is located in the nucleus. Additionally, the size of the atom is of the order of 10-10 m and that of the nucleus is of the order of 10-15 m.
