What are the in-degree and out-degree of vertex 4?
In graph theory: - The in-degree of a vertex is the number of incoming edges to that vertex.
- The out-degree of a vertex is the number of outgoing edges from that vertex.
Looking at the graph:
- Vertex 4 has 3 incoming edges (from vertices 1, 2, and 3).
- Vertex 4 has 2 outgoing edges (to vertices 1 and 3).
Thus, the in-degree of vertex 4 is 3, and the out-degree of vertex 4 is 2.
The correct answer is \( 3 \text{ and 2} \).
Let \( G \) be a simple, unweighted, and undirected graph. A subset of the vertices and edges of \( G \) are shown below.
It is given that \( a - b - c - d \) is a shortest path between \( a \) and \( d \); \( e - f - g - h \) is a shortest path between \( e \) and \( h \); \( a - f - c - h \) is a shortest path between \( a \) and \( h \). Which of the following is/are NOT the edges of \( G \)?
Match the following:
The union and intersection of the graphs G and H are respectively
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If \(A = \begin{bmatrix} 4 & 2 \\[0.3em] -3 & 3 \end{bmatrix}\), then \(A^{-1} =\)
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\(\text{I}_1 = 5V_1 + 3V_2 \)
\(\text{I}_2 = 2V_1 - 7V_2 \)
The value of \( Z_{12} \) is:
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