By adding a node \( v \) and connecting it to all vertices with an odd degree, we are ensuring that all vertices in the resultant graph have an even degree.
A graph in which all vertices have even degrees is Eulerian, meaning it has an Eulerian circuit (a closed path that uses each edge exactly once).
Thus, the resultant graph is Eulerian. Hence, the correct answer is option (1).
Let \( G \) be a simple, unweighted, and undirected graph. A subset of the vertices and edges of \( G \) are shown below.

It is given that \( a - b - c - d \) is a shortest path between \( a \) and \( d \); \( e - f - g - h \) is a shortest path between \( e \) and \( h \); \( a - f - c - h \) is a shortest path between \( a \) and \( h \). Which of the following is/are NOT the edges of \( G \)?
Match LIST-I with LIST-II

Choose the correct answer from the options given below:
Suppose a minimum spanning tree is to be generated for a graph whose edge weights are given below. Identify the graph which represents a valid minimum spanning tree?
\[\begin{array}{|c|c|}\hline \text{Edges through Vertex points} & \text{Weight of the corresponding Edge} \\ \hline (1,2) & 11 \\ \hline (3,6) & 14 \\ \hline (4,6) & 21 \\ \hline (2,6) & 24 \\ \hline (1,4) & 31 \\ \hline (3,5) & 36 \\ \hline \end{array}\]
Choose the correct answer from the options given below: