What are Kirchhoff's two laws for the electrical circuit? Find out the reading of the ammeter with the help of the given circuit, while its resistance is negligible.

The sum of currents entering a junction is equal to the sum of currents leaving the junction.
\[ \sum I_{\text{in}} = \sum I_{\text{out}} \]
Kirchhoff's Second Law (KVL - Loop Rule):The sum of all voltages around any closed loop in a circuit is zero.
\[ \sum V = 0 \]
Solution for Ammeter Reading:Applying Kirchhoff's loop rule to the given circuit:
\[ \frac{5}{4 + 2} = \frac{5}{6} \, \text{A} \]
The voltage across the parallel resistors is:
\[ V = IR = \frac{5}{6} \times 2 = \frac{10}{6} \text{ V} \]
Current through the 6Ω resistor:\[ I = \frac{10}{6} \div 6 = \frac{5}{18} \, \text{A} \]
\( \text{Ammeter reading } = \frac{5}{18} \text{ A} \)

What is the first law of Kirchhoff of the electrical circuit? Find out the potential difference between the ends of 2 \(\Omega\) resistor with the help of Kirchhoff's law. See the figure: