Question:

Using the basic proportionality theorem, prove that a line drawn through the mid-points of one side of a triangle parallel to another side bisects the third side.

Updated On: Nov 2, 2023
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Solution and Explanation

Consider the given figure in which PQ is a line segment drawn through the mid-point  P of line AB, such that PQ || BC

mid-point  P of line AB, such that PQ||BC
By using the proportionality theorem, we obtain
\(\frac{AQ}{QC}=\frac{AP}{PB}\)
\(\frac{AQ}{QC}=\frac{1}{1}\)
\(\Rightarrow\)AQ = QC
Or, Q is the midpoint of AC

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