Question:

Two vectors are given by $\vec{A} = (\hat{i} + 2j + \hat{k})$ and $\vec{B} = (3\hat{i} + 6\hat{j} + 2\hat{k})$. Another vector $\vec{C}$ has the same magnitude as $\vec{B}$ but has the same direction as $\vec{A}$. Then which of the following vectors represents $\vec{C}$ ?

Updated On: Apr 26, 2024
  • $ \frac{7}{3}\left( \hat{i} + 2\hat{j} + 2\hat{k}\right)$
  • $ \frac{3}{7}\left( \hat{i} - 2\hat{j} + 2\hat{k}\right)$
  • $ \frac{7}{9}\left( \hat{i} - 2\hat{j} + 2\hat{k}\right)$
  • $ \frac{9}{7}\left( \hat{i} + 2\hat{j} + 2\hat{k}\right)$
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The Correct Option is A

Solution and Explanation

Given, $A=\hat{i}+2 \hat{ j }+2 \hat{ k }$ and $B =3 \hat{ i }+6 \hat{ j }+2 \hat{ k }$
So, $C =\frac{\hat{ i }+2 \hat{ j }+2 \hat{ k }}{\sqrt{1+4+4}} \times \sqrt{3^{2}+6^{2}+2^{2}} $
$=\frac{\hat{ i }+2 \hat{ j }+2 \hat{ k }}{3} \times \sqrt{49}=\frac{7}{3}(\hat{i}+2 \hat{ j }+2 \hat{ k }) $
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Concepts Used:

Motion in a Plane

It is a vector quantity. A vector quantity is a quantity having both magnitude and direction. Speed is a scalar quantity and it is a quantity having a magnitude only. Motion in a plane is also known as motion in two dimensions. 

Equations of Plane Motion

The equations of motion in a straight line are:

v=u+at

s=ut+½ at2

v2-u2=2as

Where,

  • v = final velocity of the particle
  • u = initial velocity of the particle
  • s = displacement of the particle
  • a = acceleration of the particle
  • t = the time interval in which the particle is in consideration