The orbital speed of a satellite is given by:
\[v = \sqrt{\frac{GM}{R}}.\]
For satellites \(A\) and \(B\):
\[\frac{v_A}{v_B} = \sqrt{\frac{R_B}{R_A}} = \sqrt{\frac{R}{4R}} = \frac{1}{2}.\]
Thus:
\[v_B = 2v_A.\]
Given \(v_A = 3v\), the speed of \(B\) is:
\[v_B = 2 \cdot 3v = 6v.\]
A small point of mass \(m\) is placed at a distance \(2R\) from the center \(O\) of a big uniform solid sphere of mass \(M\) and radius \(R\). The gravitational force on \(m\) due to \(M\) is \(F_1\). A spherical part of radius \(R/3\) is removed from the big sphere as shown in the figure, and the gravitational force on \(m\) due to the remaining part of \(M\) is found to be \(F_2\). The value of the ratio \( F_1 : F_2 \) is: