Question

Two resistances of 100 \(\Omega\) and 200 \(\Omega\) are connected in series across a 20 V battery as shown in the figure below. The reading in a 200 \(\Omega\) voltmeter connected across the 200 \(\Omega\) esistance is _______.

Fill in the blank with the correct answer from the options given below

• A. 4V
• B. \(\frac{20}{3}V\)
• C. 10V
• D. 16V

Answer 1

The Correct Option is B

The resistances are in series, so the total resistance is

                                                                                    \(R_{total}=100\Omega+200\Omega=300\Omega\)
 

The current in the circuit is 

                                                                                           \(I=\frac{200}{300}=\frac{1}{15}A\)
 

The voltage across the \(200\Omega\) resistance is

                                                                                 \(V=IR=\frac{1}{15}\times200=\frac{200}{15}=\frac{20}{3}V\)