Two radioactive elements A and B initially have the same number of atoms. The half-life of A is the same as the average life of B. If \( \lambda_A \) and \( \lambda_B \) are the decay constants of A and B respectively, then choose the correct relation from the given options:
\( \lambda_A = 2\lambda_B \)
\( \lambda_A = \lambda_B \)
\( \lambda_A \ln 2 = \lambda_B \)
\( \lambda_A = \lambda_B \ln 2 \)
We are given that the half-life of A is the same as the average life of B. The average life \( \tau \) and half-life \( T \) are related to the decay constant \( \lambda \) by the equations: \[ T = \frac{\ln 2}{\lambda} \quad \text{and} \quad \tau = \frac{1}{\lambda} \] Since the half-life of A is the same as the average life of B, we have: \[ \lambda_A = \lambda_B \ln 2 \] Hence, the correct relation is \( \lambda_A = \lambda_B \ln 2 \).
Let $ f(x) = \begin{cases} (1+ax)^{1/x} & , x<0 \\1+b & , x = 0 \\\frac{(x+4)^{1/2} - 2}{(x+c)^{1/3} - 2} & , x>0 \end{cases} $ be continuous at x = 0. Then $ e^a bc $ is equal to
Total number of nucleophiles from the following is: \(\text{NH}_3, PhSH, (H_3C_2S)_2, H_2C = CH_2, OH−, H_3O+, (CH_3)_2CO, NCH_3\)