Question:
Two liquid drops have diameters of $1\, cm$ and $1.5\, cm$ The ratio of excess of pressures inside them is
Two liquid drops have diameters of $1\, cm$ and $1.5\, cm$ The ratio of excess of pressures inside them is
Updated On: Jun 6, 2024
- $ 1:1 $
- $ 5:3 $
- $ 2:3 $
- $ 3:2 $
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The Correct Option is D
Solution and Explanation
Excess pressure inside a liquid drop
$\Delta p=\frac{2 T}{R}$
where $T$ is surface tension and $R$ is radius of liquid drop.
$=\frac{\Delta p_{1}}{\Delta p_{2}}=\frac{R_{2}}{R_{1}}$
$=\frac{0.75}{0.50}$
$\Rightarrow \frac{\Delta p_{1}}{\Delta p_{2}}=\frac{3}{2}$
$\Delta p=\frac{2 T}{R}$
where $T$ is surface tension and $R$ is radius of liquid drop.
$=\frac{\Delta p_{1}}{\Delta p_{2}}=\frac{R_{2}}{R_{1}}$
$=\frac{0.75}{0.50}$
$\Rightarrow \frac{\Delta p_{1}}{\Delta p_{2}}=\frac{3}{2}$
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