Question

Two inductors each of \(50mH\) are connected in parallel, what is the equivalent inductance?

Answer 1

When inductors are connected in parallel, the equivalent inductance \((L_eq)\) can be calculated using the formula:
\(1/L_eq = 1/L1 + 1/L2 + 1/L3 + .….\)
In this case, you have two inductors each with an inductance of \(50 mH.\) Plugging in the values into the formula:
\(1/L_eq = 1/50mH + 1/50mH\)
To add the fractions, you need a common denominator:
\(1/L_eq = (1/50mH + 1/50mH)/(1mH)\)
Simplifying the numerator:
\(1/L_eq = (2/50mH)/(1mH)\)
\(1/L_eq = 2/50\)
Inverting both sides:
\(L_eq = 50/2\)
\(L_eq = 25 mH\)
Therefore, the equivalent inductance of two \(50 mH\) inductors connected in parallel is \(25 mH.\)