When inductors are connected in parallel, the equivalent inductance \((L_eq)\) can be calculated using the formula: \(1/L_eq = 1/L1 + 1/L2 + 1/L3 + .….\) In this case, you have two inductors each with an inductance of \(50 mH.\) Plugging in the values into the formula: \(1/L_eq = 1/50mH + 1/50mH\) To add the fractions, you need a common denominator: \(1/L_eq = (1/50mH + 1/50mH)/(1mH)\) Simplifying the numerator: \(1/L_eq = (2/50mH)/(1mH)\) \(1/L_eq = 2/50\) Inverting both sides: \(L_eq = 50/2\) \(L_eq = 25 mH\) Therefore, the equivalent inductance of two \(50 mH\) inductors connected in parallel is \(25 mH.\)
Electromagnetic Induction is a current produced by the voltage production due to a changing magnetic field. This happens in one of the two conditions:-
When we place the conductor in a changing magnetic field.
When the conductor constantly moves in a stationary field.