Question

Two identical circular wires of radius 20 cm and carrying current \(\sqrt2 \)A are placed in perpendicular planes as shown in figure. The net magnetic field at the centre of the circular wires is _________ × 10^{-8} T.
 

Answer 1

Correct Answer: 628

\(\begin{aligned} & \overrightarrow{B_{n e t}}=\frac{\mu_0 i}{2 r} \hat{i}+\frac{\mu_0 i}{2 r} \hat{\jmath} \\ & \Rightarrow B_{\text {net }}=\frac{\mu_0 i}{2 r} \sqrt{2}=4 \pi \times 10^{-7} \times \sqrt{2} \times \sqrt{2} \times \frac{1}{2 \times 0.2}=2 \times 3.14 \times 10^{-6}=628 \times 10^{-8} \mathrm{~T} \end{aligned}\)