Question:
Two identical charges repel each other with a force equal to $10\, mgwt$ when they are $0.6\, m$ apart in air.$( g = 10 ms^{-2} )$ The value of each charge is
Two identical charges repel each other with a force equal to $10\, mgwt$ when they are $0.6\, m$ apart in air.$( g = 10 ms^{-2} )$ The value of each charge is
Updated On: May 30, 2022
- 2 mc
- $2 \times 10^{-7}\,C$
- 2 nc
- $2 \mu C$
Hide Solution
Verified By Collegedunia
The Correct Option is D
Solution and Explanation
Coulomb force is given by
$F= \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}} $
$\therefore\left(10 \times 10^{-3}\right) \times 10= \frac{\left(9 \times 10^{9}\right) \times q^{2}}{(0.6)^{2}} $
$\left[\because q_{1}=q_{2}=q\right]$
or $q^{2} =\frac{10^{-1} \times 0.36}{9 \times 10^{9}} $
$=4 \times 10^{-12} $
$q =2 \times 10^{-6} \,C$
$=2 \,\mu \,C$
$F= \frac{1}{4 \pi \varepsilon_{0}} \frac{q_{1} q_{2}}{r^{2}} $
$\therefore\left(10 \times 10^{-3}\right) \times 10= \frac{\left(9 \times 10^{9}\right) \times q^{2}}{(0.6)^{2}} $
$\left[\because q_{1}=q_{2}=q\right]$
or $q^{2} =\frac{10^{-1} \times 0.36}{9 \times 10^{9}} $
$=4 \times 10^{-12} $
$q =2 \times 10^{-6} \,C$
$=2 \,\mu \,C$
Was this answer helpful?
0
0
Top Questions on Electric Field
- An electron is released in the field generated by a non-conductivity sheet of uniform surface charge density $ \sigma $. The rate of change of de-Broglie wavelength associated with the electron varies inversely as the $ n $th power of the distance travelled. Find the value of $ n $.
- JEE Main - 2025
- Physics
- Electric Field
- An electron of mass \( m \) with an initial velocity \( \vec{v} = v_0 \hat{i} (v_0>0) \) enters an electric field \( \vec{E} = -E_0 \hat{k} \). If the initial de Broglie wavelength is \( \lambda_0 \), the value after time \( t \) would be:
- JEE Main - 2025
- Physics
- Electric Field
- A metallic sphere of radius \( R \) is charged to a potential \( V \). The magnitude of the electric field at a distance \( r \, (r > R) \) from the center of the sphere is:
- MHT CET - 2024
- Physics
- Electric Field
- \( \sigma \) is the uniform surface charge density of a thin spherical shell of radius \( R \). The electric field at any point on the surface of the spherical shell is:
- MHT CET - 2024
- Physics
- Electric Field
- 1 tesla =
- AP POLYCET - 2024
- Physics
- Electric Field
View More Questions
Questions Asked in KCET exam
- Three polaroid sheets are co-axially placed as indicated in the diagram. Pass axes of the polaroids 2 and 3 make 30° and 90° with pass axes of polaroid sheet 1. If \( I_1 \) is the intensity of the incident unpolarised light entering sheet 1, the intensity of the emergent light through sheet 3 is
- KCET - 2024
- Polarization
- If lines $\frac{x - 1}{-3} = \frac{y - 2}{2k} = \frac{z - 3}{2}$ and $\frac{x - 1}{3k} = \frac{y - 5}{1} = \frac{z - 6}{-5}$ are mutually perpendicular, then $k$ is equal to:
- KCET - 2024
- Straight lines
- In the following scheme of reaction.
X, Y and Z respectively are:- KCET - 2024
- Haloalkanes and Haloarenes
- 8.8 g of monohydric alcohol reacts with ethyl magnesium iodide, releasing 2240 $cm^3$ of ethane at STP. This monohydric alcohol forms a carbonyl compound that answers Tollen’s test. The alcohol is:
- KCET - 2024
- Alcohols, Phenols and Ethers
- Let $\vec{a}$ and $\vec{b}$ be two unit vectors and $\theta$ is the angle between them. Then $\vec{a} + \vec{b}$ is a unit vector if:
- KCET - 2024
- Vectors
View More Questions
Concepts Used:
Electric Field
Electric Field is the electric force experienced by a unit charge.
The electric force is calculated using the coulomb's law, whose formula is:
\(F=k\dfrac{|q_{1}q_{2}|}{r^{2}}\)
While substituting q2 as 1, electric field becomes:
\(E=k\dfrac{|q_{1}|}{r^{2}}\)
SI unit of Electric Field is V/m (Volt per meter).