Question

Two cards are drawn without replacement. The probability distribution of number of aces is given by:

• A.

  X	0	1	2
  P(X)	\(\frac{188}{221}\)	\(\frac{32}{221}\)	\(\frac{1}{221}\)

• B.

  X	0	1	2
  P(X)	\(\frac{144}{169}\)	\(\frac{24}{169}\)	\(\frac{1}{169}\)

• C.

  X	0	1	2
  P(X)	\(\frac{188}{221}\)	\(\frac{24}{221}\)	\(\frac{1}{221}\)

• D.

  X	0	1	2
  P(X)	\(\frac{188}{221}\)	\(\frac{1}{221}\)	\(\frac{24}{221}\)

Answer 1

The Correct Option is A

The correct option is (A):

X	0	1	2
P(X)	\(\frac{188}{221}\)	\(\frac{32}{221}\)	\(\frac{1}{221}\)