The correct answer is 2
\(I_{R_1}=I_1+I_2+2\sqrt{I_1I_2}\cos\phi\)
\(I_A=I+4I+2\sqrt{I⋅4I}\cos90^∘=5I\)
\(I_B=I+4I+2\sqrt{I⋅4I}\cos60^∘=7I\)
\(I_B–I_A=2I\)
\(\therefore\) value of x is 2
Calculate the angle of minimum deviation of an equilateral prism. The refractive index of the prism is \(\sqrt{3}\). Calculate the angle of incidence for this case of minimum deviation also.
For the thermal decomposition of \( N_2O_5(g) \) at constant volume, the following table can be formed, for the reaction mentioned below: \[ 2 N_2O_5(g) \rightarrow 2 N_2O_4(g) + O_2(g) \] Given: Rate constant for the reaction is \( 4.606 \times 10^{-2} \text{ s}^{-1} \).