Two bar magnets oscillate in a horizontal plane in earth’s magnetic field with time periods of 3 s and 4 s respectively. If their moments of inertia are in the ratio of 3 : 2, then the ratio of their magnetic moments will be :
2 : 1
8 : 3
1 : 3
27 : 16
The correct answer is (B) : 8 : 3
\(T=2π\sqrt{\frac{I}{MB_H}}\)
\(⇒\frac{T_1}{T_2}=\sqrt{\frac{I_1}{I_2}}\sqrt{\frac{M_2}{M_1}}\)
\(⇒\frac{3}{4}=\sqrt{\frac{3}{2}}\sqrt{\frac{M_2}{M_1}}\)
\(\frac{M_1}{M_2}=\frac{3}{2}\times\frac{16}{9}\)
\(=\frac{8}{3}\)
A current-carrying coil is placed in an external uniform magnetic field. The coil is free to turn in the magnetic field. What is the net force acting on the coil? Obtain the orientation of the coil in stable equilibrium. Show that in this orientation the flux of the total field (field produced by the loop + external field) through the coil is maximum.
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Read More: Magnetism and Matter