Two bar magnets oscillate in a horizontal plane in earth’s magnetic field with time periods of 3 s and 4 s respectively. If their moments of inertia are in the ratio of 3 : 2, then the ratio of their magnetic moments will be :
2 : 1
8 : 3
1 : 3
27 : 16
The correct answer is (B) : 8 : 3
\(T=2π\sqrt{\frac{I}{MB_H}}\)
\(⇒\frac{T_1}{T_2}=\sqrt{\frac{I_1}{I_2}}\sqrt{\frac{M_2}{M_1}}\)
\(⇒\frac{3}{4}=\sqrt{\frac{3}{2}}\sqrt{\frac{M_2}{M_1}}\)
\(\frac{M_1}{M_2}=\frac{3}{2}\times\frac{16}{9}\)
\(=\frac{8}{3}\)
A particle of charge $ q $, mass $ m $, and kinetic energy $ E $ enters in a magnetic field perpendicular to its velocity and undergoes a circular arc of radius $ r $. Which of the following curves represents the variation of $ r $ with $ E $?
20 mL of sodium iodide solution gave 4.74 g silver iodide when treated with excess of silver nitrate solution. The molarity of the sodium iodide solution is _____ M. (Nearest Integer value) (Given : Na = 23, I = 127, Ag = 108, N = 14, O = 16 g mol$^{-1}$)
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Read More: Magnetism and Matter