Question:

A current-carrying loop can be considered as a magnetic dipole placed along its axis. Explain.

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A current-carrying loop generates a magnetic dipole field, and its magnetic dipole moment is given by \( \mathbf{M} = I A \hat{n} \).
Updated On: Feb 26, 2025
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Solution and Explanation

A current-carrying loop generates a magnetic field similar to that of a magnetic dipole. The magnetic dipole moment \( \mathbf{M} \) of the loop is given by: \[ \mathbf{M} = I A \hat{n} \] Where: - \( I \) is the current in the loop, - \( A \) is the area of the loop, - \( \hat{n} \) is the unit vector normal to the plane of the loop (along the axis of the loop). Thus, the current loop behaves like a magnetic dipole with a magnetic dipole moment \( \mathbf{M} \) directed along the axis of the loop.
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