Question:

\( \triangle PQR \) मध्ये, रेषा PM मध्यमा आहे: PM = 9 आणि \( PQ^2 + PR^2 = 290 \), तर QR काय आहे? 
 

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तरंगाच्या त्रिकोणासाठी \( QR^2 = PQ^2 + PR^2 - 2 \times PM^2 \) वापरता येते.
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Solution and Explanation

आता दिलेले आहे:
\[ PM = 9, PQ^2 + PR^2 = 290 \]
त्यामुळे,
\[ QR^2 = PQ^2 + PR^2 - 2 \times PM^2 \]
\[ QR^2 = 290 - 2 \times 9^2 = 290 - 162 = 128 \]
\[ QR = \sqrt{128} \approx 11.31 \text{ युनिट्स} \]
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