The problem requires identifying the total number of \(\sigma\) and \(\pi\) bonds in an ethene (\(C_2H_4\)) molecule.
Structure of Ethene (\(C_2H_4\)): The ethene molecule consists of two carbon atoms (\(C\)) and four hydrogen atoms (\(H\)).
Bonding Details:
Type of Bond | Number of Bonds |
---|---|
\(\sigma\) bonds (C-C) | 1 |
\(\sigma\) bonds (C-H) | 4 |
\(\pi\) bonds (C-C) | 1 |
Total Bonds:
Therefore, ethene has 5 \(\sigma\) and 1 \(\pi\) bonds.
To determine the total number of σ and π bonds in an ethene (ethylene) molecule, we must examine its molecular structure. Ethene has the chemical formula C2H4. The structure of ethene consists of:
In a double bond, there is one σ (sigma) bond and one π (pi) bond:
For the ethene molecule, count as follows:
Type of Bond | Number |
---|---|
σ bonds (total) | 5 |
π bonds (total) | 1 |
Hence, the total number of bonds in the ethene molecule is 5 σ and 1 π bond.
Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is (are):
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
A solid cylinder of mass 2 kg and radius 0.2 m is rotating about its own axis without friction with angular velocity 5 rad/s. A particle of mass 1 kg moving with a velocity of 5 m/s strikes the cylinder and sticks to it as shown in figure.
The angular velocity of the system after the particle sticks to it will be: