Question

Total number of antibonding electrons present in $O_2$ will be

• A. 6
• B. 8
• C. 4
• D. 2

Answer 1

The Correct Option is A

$O _{2}(\sigma 1 s)^{2}\left(\sigma^{*} 1 s\right)^{2}(\sigma 2 s)^{2}\left(\sigma^{*} 2 s\right)^{2}\left(\sigma 2 p_{z}\right)^{2}\left(\pi 2 p_{x}^{2}=\pi 2 p_{y}^{2}\right)\left(\pi^{*} 2 p_{x}^{1}=\pi^{*} 2 p_{y}^{1}\right)$ Thus, there are total 6 electrons in antibonding orbitals.