Side of regular octagon = 5 cm
Area of trapezium ABCH = Area of trapezium DEFG
Area of trapezium ABCH = \(\frac{1}{2} × \)(AB + CH) \(×\) AI
\(= \frac{1}{2} ×\) (5 m + 11 m) \(×\) 4 m
\(= \frac{1}{2} ×\) 16 m \(×\) 4 m
= 32 m²
Area of rectangle HGDC \(= 11 × 5 = 55\) m2
Area of octagon = Area of trapezium ABCH + Area of trapezium DEFG + Area of rectangle HGDC
= 32 m2 + 32 m2 + 55 m2 = 119 m2
A | B | ||
---|---|---|---|
(i) | Kharif crops | (a) | Food for cattle |
(ii) | Rabi crops | (b) | Urea and super phosphate |
(iii) | Chemical fertilizers | (c) | Animal excreta, cow dung urine and plant waste |
(iv) | Organic manure | (d) | Wheat, gram, pea |
(e) | Paddy and maize |