Question

Length of the fence of a trapezium shaped field ABCD is 120 m. If BC = 48 m, CD = 17 m and AD = 40 m, find the area of this field. Side AB is perpendicular to the parallel sides AD and BC.

Answer 1

 

Length of the fence of trapezium ABCD = AB + BC + CD + DA 
120 m = AB + 48 m + 17 m + 40 m 
AB = 120 m - 105 m = 15 m 
Area of the field ABCD 
= \(\frac{1}{2}\) × (AD + BC) × AB

= \(\frac{1}{2}\) × (40 + 48) × 15 m

= \(\frac{1}{2}\) × (88 m) × 15 m
= 44 m × 15 m
= 660 m²

Thus, area of the field ABCD is 660 m²