As isothermal \( U = 0 \) and the process is irreversible:
\[Q = -W = -\left[-P_{\text{ext}}(V_2 - V_1)\right]\]
\[Q = 5 \times (20 - 60) = -200 \, \text{atm-L}\]
Given:
\[P_{\text{ext}} = 5 \, \text{atm}, \quad V_1 = 60 \, \text{L}, \quad V_2 = 20 \, \text{L}\]
Substituting the values:
\[Q = 5 \times (20 - 60) = -200 \, \text{atm-L}\]
Thus, the heat exchange for the compression is \( 200 \, \text{Lit. atm} \).
Match List - I with List - II.
Consider the following statements:
(A) Availability is generally conserved.
(B) Availability can neither be negative nor positive.
(C) Availability is the maximum theoretical work obtainable.
(D) Availability can be destroyed in irreversibility's.
Let \( S = \left\{ m \in \mathbb{Z} : A^m + A^m = 3I - A^{-6} \right\} \), where
\[ A = \begin{bmatrix} 2 & -1 \\ 1 & 0 \end{bmatrix} \]Then \( n(S) \) is equal to ______.
Let \( T_r \) be the \( r^{\text{th}} \) term of an A.P. If for some \( m \), \( T_m = \dfrac{1}{25} \), \( T_{25} = \dfrac{1}{20} \), and \( \displaystyle\sum_{r=1}^{25} T_r = 13 \), then \( 5m \displaystyle\sum_{r=m}^{2m} T_r \) is equal to: