As isothermal \( U = 0 \) and the process is irreversible:
\[Q = -W = -\left[-P_{\text{ext}}(V_2 - V_1)\right]\]
\[Q = 5 \times (20 - 60) = -200 \, \text{atm-L}\]
Given:
\[P_{\text{ext}} = 5 \, \text{atm}, \quad V_1 = 60 \, \text{L}, \quad V_2 = 20 \, \text{L}\]
Substituting the values:
\[Q = 5 \times (20 - 60) = -200 \, \text{atm-L}\]
Thus, the heat exchange for the compression is \( 200 \, \text{Lit. atm} \).
The left and right compartments of a thermally isolated container of length $L$ are separated by a thermally conducting, movable piston of area $A$. The left and right compartments are filled with $\frac{3}{2}$ and 1 moles of an ideal gas, respectively. In the left compartment the piston is attached by a spring with spring constant $k$ and natural length $\frac{2L}{5}$. In thermodynamic equilibrium, the piston is at a distance $\frac{L}{2}$ from the left and right edges of the container as shown in the figure. Under the above conditions, if the pressure in the right compartment is $P = \frac{kL}{A} \alpha$, then the value of $\alpha$ is ____