Question:

Three fair dice are rolled simultaneously. Let a, b, c be the numbers on the top of the dice. Then the probability that min(a, b, c) =6 is

Updated On: Jun 5, 2024
  • \(\frac{1}{216}\)
  • \(\frac{1}{36}\)
  • \(\frac{1}{6}\)
  • \(\frac{11}{216}\)
  • \(\frac{5}{6}\)
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The Correct Option is A

Solution and Explanation

The correct option is (A) : \(\frac{1}{216}\)
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