Question

Three coins are tossed together. The probability that exactly one coin shows head, is

• A. \(\frac{1}{8}\)
• B. \(\frac{1}{4}\)
• C. \(1\)
• D. \(\frac{3}{8}\)

Hint:

Probability of exactly \(k\) successes in \(n\) trials = \(\binom{n}{k} \times (p)^k \times (1-p)^{n-k}\). For fair coins, \(p = \frac{1}{2}\).

Answer 1

The Correct Option is D

Total possible outcomes when tossing 3 coins \(= 2^3 = 8\). Number of ways to get exactly one head \(= \binom{3}{1} = 3\). Probability \(= \frac{3}{8}\).