Given:
Three coins are tossed together.
Find the probability that at least one head appears.
Step 1: Total possible outcomes
Each coin has 2 outcomes (Head or Tail).
Total outcomes for 3 coins = \(2^3 = 8\).
Step 2: Find probability of complementary event (no heads)
No heads means all tails.
Number of ways = 1 (TTT)
Probability of no heads = \(\frac{1}{8}\).
Step 3: Calculate required probability
Probability of at least one head = \(1 - \text{Probability of no heads}\)
\[
= 1 - \frac{1}{8} = \frac{7}{8}
\]