Given:
Two dice are rolled together.
Find the probability that the sum of the numbers on the two dice is more than 9.
Step 1: Total possible outcomes
Each die has 6 faces.
Total outcomes when two dice are rolled = \(6 \times 6 = 36\).
Step 2: Find favorable outcomes (sum > 9)
Possible sums greater than 9 are 10, 11, and 12.
- Sum = 10: (4,6), (5,5), (6,4) → 3 outcomes
- Sum = 11: (5,6), (6,5) → 2 outcomes
- Sum = 12: (6,6) → 1 outcome
Total favorable outcomes = \(3 + 2 + 1 = 6\).
Step 3: Calculate probability
\[
\text{Probability} = \frac{\text{Favorable outcomes}}{\text{Total outcomes}} = \frac{6}{36} = \frac{1}{6}
\]
Final Answer:
\[
\boxed{\frac{1}{6}}
\]