Question

Two dice are rolled together. The probability of getting a sum more than 9 is

• A. \(\dfrac{5}{6}\)
• B. \(\dfrac{5}{18}\)
• C. \(\dfrac{1}{6}\)
• D. \(\dfrac{1}{2}\)

Hint:

List all outcome pairs to count favorable ones, especially when dealing with two dice.

Answer 1

The Correct Option is B

Total outcomes when two dice are rolled = 36
Favorable outcomes for sum>9: (4,6), (5,5), (5,6), (6,4), (6,5), (6,6) = 6 outcomes \[ \text{Probability} = \dfrac{6}{36} = \dfrac{1}{6} \] Correction — missing (3,6) → no, not >9. Let’s list again: Sums more than 9 are 10, 11, 12:
- Sum = 10: (4,6), (5,5), (6,4) → 3
- Sum = 11: (5,6), (6,5) → 2
- Sum = 12: (6,6) → 1
Total favorable outcomes = 6
So probability = \(\dfrac{6}{36} = \dfrac{1}{6}\) Correct answer: (C) \(\dfrac{1}{6}\)