Question

There are two cuboidal boxes as shown in the adjoining figure. Which box requires the lesser amount of material to make?

Answer 1

We know that, 
Total surface area of the cuboid = \(2 (lh + bh + lb) \)
Total surface area of the cube =\( 6 (l)^ 2 \)
Total surface area of cuboid (a) = [2{(60) (40) + (40) (50) + (50) (60)}] cm² 
= [2(2400 + 2000 + 3000)] cm² 
= (2\(\times\) 7400) cm² 
= 14800 cm² 
Total surface area of cube (b) = 6 (50 cm)² = 15000 cm² 
Thus, the cuboidal box (a) will require lesser amount of material.