Let the sides of the cuboid be \( 4x \), \( 5x \), and \( 6x \), where \( x \) is the constant of proportionality.
The surface area of a cuboid is given by the formula:
\[
A = 2(lw + lh + wh)
\]
where \( l \), \( w \), and \( h \) are the length, width, and height of the cuboid, respectively.
Substitute the values of \( l = 4x \), \( w = 5x \), and \( h = 6x \) into the formula:
\[
A = 2 \left( (4x)(5x) + (4x)(6x) + (5x)(6x) \right)
\]
\[
A = 2 \left( 20x^2 + 24x^2 + 30x^2 \right)
\]
\[
A = 2 \times 74x^2 = 148x^2
\]
We are given that the total surface area is 1332 square cm:
\[
148x^2 = 1332
\]
\[
x^2 = \frac{1332}{148} = 9
\]
\[
x = 3
\]
Now, substitute \( x = 3 \) into the sides:
- \( l = 4x = 12 \)
- \( w = 5x = 15 \)
- \( h = 6x = 18 \)
Thus, the sides of the cuboid are \( 12 \), \( 15 \), and \( 18 \).