The work done by the force \( \mathbf{F} = (4\hat{i} -3\hat{j} + 2\hat{k}) \) N in giving a 1 nC charge a displacement of \( (10\hat{i} + 2\hat{j} -7\hat{k}) \) m is:
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Work done is calculated as \( W = \mathbf{F} \cdot \mathbf{d} \).
The work done by a force is given by the dot product:
\[
W = \mathbf{F} \cdot \mathbf{d}
\]
\[
W = (4\hat{i} -3\hat{j} + 2\hat{k}) \cdot (10\hat{i} + 2\hat{j} -7\hat{k})
\]
\[
W = (4 \times 10) + (-3 \times 2) + (2 \times -7)
\]
\[
W = 40 - 6 - 14 = 20 \text{ nJ}
\]