Question:

The wavelength of the de-Broglie wave associated with a thermal neutron of mass $m$ at absolute temperature $T$ is given by (here, $K$ is the Boltzmann constant)

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The de-Broglie wavelength is inversely proportional to the square root of the thermal energy of the particle.
Updated On: Mar 30, 2025
  • $\frac{h}{\sqrt{mK T}}$
  • $\frac{\sqrt{mK T}}{h}$
  • $\frac{2h}{\sqrt{3m K T}}$
  • $\frac{h}{\sqrt{2m K T}}$
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The Correct Option is C

Solution and Explanation


The de-Broglie wavelength of a thermal neutron is given by: \[ \lambda = \frac{h}{\sqrt{3mK T}} \]
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