The volume strength of $1 \,M H _{2} O _{2}$ is
(Molar mass of $\left. H _{2} O _{2}=34 \,g\, mol ^{-1}\right)$
- 16.8
- 11.35
- 22.4
- 5.6
The Correct Option is B
Solution and Explanation
Top Questions on Stoichiometry and Stoichiometric Calculations
- How many grams of sodium chloride (NaCl) are produced when 2.0 moles of sodium (Na) react with excess chlorine gas (Cl\(_2\)? The balanced chemical equation for the reaction is: \[ 2 \, \text{Na} (s) + \text{Cl}_2 (g) \rightarrow 2 \, \text{NaCl} (s) \]
- MHT CET - 2025
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- How many molecules of carbon dioxide are formed when 0.6 g carbon is burnt in air?
- MHT CET - 2025
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- What is the number of moles of oxygen atoms in 4.0 g of \( \text{O}_2 \)?
- MHT CET - 2025
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- In the reaction \( 2\text{SO}_2 + \text{O}_2 \rightarrow 2\text{SO}_3 \), if 64 g of \(\text{SO}_2\) reacts completely, how many grams of \(\text{SO}_3\) are produced? (Molar mass of \(\text{SO}_2 = 64 \, \text{g/mol}, \text{SO}_3 = 80 \, \text{g/mol}\))
- BITSAT - 2025
- Chemistry
- Stoichiometry and Stoichiometric Calculations
- What is the volume of oxygen required for complete combustion of 0.25 mole of methane at S.T.P.?
- MHT CET - 2025
- Chemistry
- Stoichiometry and Stoichiometric Calculations
Questions Asked in JEE Main exam
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
- JEE Main - 2025
- Molecular Orbital Theory
- The increase in pressure required to decrease the volume of a water sample by 0.2percentage is \( P \times 10^5 \, \text{Nm}^{-2} \). Bulk modulus of water is \( 2.15 \times 10^9 \, \text{Nm}^{-2} \). The value of \( P \) is ________________.
- JEE Main - 2025
- System of Particles & Rotational Motion
The velocity-time graph of an object moving along a straight line is shown in the figure. What is the distance covered by the object between \( t = 0 \) to \( t = 4s \)?
- JEE Main - 2025
- Kinetic Energy
- Let \( P_n = \alpha^n + \beta^n \), \( P_{10} = 123 \), \( P_9 = 76 \), \( P_8 = 47 \), and \( P_1 = 1 \). The quadratic equation whose roots are \( \frac{1}{\alpha} \) and \( \frac{1}{\beta} \) is:
- JEE Main - 2025
- Sequences and Series
- The value of current \( I \) in the electrical circuit as given below, when the potential at \( A \) is equal to the potential at \( B \), will be ________________________ A.
- JEE Main - 2025
- Electrical Circuits
JEE Main Notification
GMC Azamgarh Admission 2025: Dates, Courses, Fees, Eligibility, SelectJuly 22, 2025Concepts Used:
Stoichiometry
Stoichiometry is founded on the law of conservation of mass where the total mass of the reactants equals the total mass of the products, leading to the insight that the relations among quantities of reactants and products typically form a ratio of positive integers. This means that if the amounts of the separate reactants are known, then the amount of the product can be calculated. Conversely, if one reactant has a known quantity and the quantity of the products can be empirically determined, then the amount of the other reactants can also be calculated.
Stoichiometry helps us determine how much substance is needed or is present. Things that can be measured are;
- Reactants and Products mass
- Molecular weight
- Chemical equations
- Formulas
Stoichiometric Coefficient
The Stoichiometric coefficient of any given component is the number of molecules and/or formula units that participate in the reaction as written.
Mole Ratios
The mass of one mole of a substance in grams is called molar mass. The molar mass of one mole of a substance is numerically equal to the atomic/molecular formula mass.