First, calculate the number of moles of \( \text{O}_2 \) in 4.0 g of \( \text{O}_2 \). The molar mass of \( \text{O}_2 \) is:
\[
\text{Molar mass of } \text{O}_2 = 32 \, \text{g/mol}
\]
Now, calculate the moles of \( \text{O}_2 \):
\[
\text{Moles of } \text{O}_2 = \frac{\text{Mass of } \text{O}_2}{\text{Molar mass of } \text{O}_2} = \frac{4.0 \, \text{g}}{32 \, \text{g/mol}} = 0.125 \, \text{mol}
\]
Since each molecule of \( \text{O}_2 \) contains 2 oxygen atoms, the number of moles of oxygen atoms will be:
\[
\text{Moles of oxygen atoms} = 2 \times 0.125 \, \text{mol} = 0.25 \, \text{mol}
\]
Thus, the number of moles of oxygen atoms in 4.0 g of \( \text{O}_2 \) is \( 0.25 \, \text{mol} \).