Question:

The velocity of a travelling plane wave given by \[ y = 10^{-2} \sin \left( 200t - \frac{x}{5} \right) m, \] is

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The speed of a wave is given by the ratio of its angular frequency $\omega$ to the wave number $k$.
Updated On: Mar 5, 2025
  • $10 \, \text{m}^{-1}$
  • $500 \, \text{m}^{-1}$
  • $400 \, \text{m}^{-1}$
  • $5 \, \text{m}^{-1}$
  • $1000 \, \text{m}^{-1}$

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The Correct Option is

Solution and Explanation

Step 1: The standard form of a travelling wave equation is: \[ y = A \sin (\omega t - kx) \] where $\omega$ is the angular frequency, $k$ is the wave number, and the wave velocity $v$ is given by: \[ v = \frac{\omega}{k} \] Step 2: From the given equation, we compare terms: \[ \omega = 200, \quad k = \frac{1}{5} \] Step 3: Using the wave velocity formula: \[ v = \frac{200}{1/5} = 200 \times 5 = 1000 { ms}^{-1} \] Step 4: Therefore, the correct answer is (E).

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