Step 1: {Find the magnitudes of the vectors}
Compute the magnitudes:
\[
|\vec{a}| = \sqrt{2^2 + (-1)^2 + 1^2} = \sqrt{6}, \,\] \[|\vec{b}| = \sqrt{1^2 + (-3)^2 + (-5)^2} = \sqrt{35}, \,\]\[ |\vec{c}| = \sqrt{(-3)^2 + 4^2 + 4^2} = \sqrt{41}.
\]
Step 2: {Check for right angle using dot products}
Calculate \( \vec{a} \cdot \vec{b} \), \( \vec{b} \cdot \vec{c} \), and \( \vec{c} \cdot \vec{a} \). If one is zero, the triangle is right-angled. For example:
\[
\vec{a} \cdot \vec{c} = (2)(-3) + (-1)(4) + (1)(4) = -6 - 4 + 4 = 0.
\]
Step 3: {Conclude the type of triangle}
Since \( \vec{a} \cdot \vec{c} = 0 \), the triangle is right-angled.