Question

The variation of the stopping potential \( V_0 \) with the frequency \( \nu \) of the incident radiation for four metals A, B, C, and D is shown in the figure. For the same frequency of incident radiation producing photo-electrons in all metals, the kinetic energy of photo-electrons will be maximum for which metal?

• A. \( A \)
• B. \( B \)
• C. \( C \)
• D. \( D \)

Hint:

The kinetic energy of photoelectrons is related to the stopping potential: \( K.E. = eV_0 \), where \( e \) is the charge of an electron. The metal with the highest stopping potential at a given frequency will have the maximum kinetic energy of photoelectrons.

Answer 1

The Correct Option is A

The stopping potential \( V_0 \) is directly related to the kinetic energy of the photoelectrons. The stopping potential increases with the frequency of the incident radiation, and the maximum kinetic energy of the photoelectrons will occur for the metal with the largest stopping potential for a given frequency. In the graph, the stopping potential \( V_0 \) is highest for metal A at a given frequency, indicating that the kinetic energy of the photoelectrons is maximum for metal A.