Question:

The value of the limit as $x$ approaches $0$ for $\frac{\sin(5x){x}$ is}

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Always try to express trigonometric limits in terms of $\frac{\sin x}{x}$ when $x$ approaches zero.
Updated On: Jan 20, 2026
  • 1
  • 5
  • $\frac{1}{5}$
  • 0
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The Correct Option is B

Solution and Explanation

Step 1: Use the standard limit.
A standard limit in calculus is: \[ \lim_{x \to 0} \frac{\sin x}{x} = 1 \]
Step 2: Rewrite the given expression.
\[ \frac{\sin(5x)}{x} = 5 \cdot \frac{\sin(5x)}{5x} \]
Step 3: Apply the limit.
As $x \to 0$, $5x \to 0$, hence \[ \lim_{x \to 0} \frac{\sin(5x)}{5x} = 1 \]
Step 4: Final calculation.
\[ \lim_{x \to 0} \frac{\sin(5x)}{x} = 5 \times 1 = 5 \]
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