Step 1: Express 625 as a power of 5 We know that \[ 625 = 5^4 \] Step 2: Use change of base identity \[ \log_{625} 5 = \log_{5^4} 5 \] Using the identity \(\log_{a^m} b = \frac{1}{m} \log_a b\), we get \[ \log_{5^4} 5 = \frac{1}{4} \log_5 5 \] Step 3: Simplify further \[ \log_5 5 = 1 \] So, \[ \log_{625} 5 = \frac{1}{4} \]
The correct option is (B): \(\frac{1}{4}\)
The product of all solutions of the equation \(e^{5(\log_e x)^2 + 3 = x^8, x > 0}\) , is :