Step 1: Recall the logarithmic identity
We are asked to find \( \log_2 32 \).
The logarithmic identity \( \log_b x = y \) means that \( b^y = x \). In this case, \( \log_2 32 = y \) means that \( 2^y = 32 \).
Step 2: Express 32 as a power of 2
We know that:
\[
32 = 2^5
\]
Thus, the equation becomes:
\[
2^y = 2^5
\]
Step 3: Solve for \( y \)
Since the bases are the same, we can equate the exponents:
\[
y = 5
\]
Answer: Therefore, \( \log_2 32 = 5 \). So, the correct answer is option (1).